Hacky Easter 2017 Teaser , Riddle 7 Solution

RIDDLE 7

Hwldp wx, Euxwh! QYAVL

this seems to be an encryption some how, but it is not clear

doing a quick search for Euxwh on google, i found it as an example of Ceaser Cipher

so using Ceaser Cipher (explanation is here https://mysterytriplets.wordpress.com/2014/11/13/hw-wx-euxwh-learning-the-cesarean-cipher-3-letters-back/)

the code is "NVXSI"

Hacky Easter 2017 Teaser , Riddle 6 Solution

RIDDLE 6

--- -. . / -- --- .-. . / .... . .-. . ---... / .--- .- --- -- -.--

this looks like Morse code, using any online decode (i use http://morsecode.scphillips.com/translator.html )

the translated text is : ONE MORE HERE: JAOMY

the code is "KAOMY"

Hacky Easter 2017 Teaser , Riddle 5 Solution

RIDDLE 5

3a3ea00cfc35332cedf6e5e9a32e94da
9d5ed678fe57bcca610140957afab571
f09564c9ca56850d4cd6b3319e541aee
5dbc98dcc983a70728bd082d1a47546e
7fc56270e7a70fa81a5935b72eacbe29

as the code is 5 characters, then each line will be a letter 

trying with MD5 decode (i use http://md5decrypt.net/en/)

the code is "EBQSA"

Hacky Easter 2017 Teaser , Riddle 4 Solution

RIDDLE 4

eval(function(p,a,c,k,e,d){e=function(c){return c};if(!''.replace(/^/,String)){while(c--){d[c]=k[c]||c}k=[function(e){return d[e]}];e=function(){return'\\w+'};c=1};while(c--){if(k[c]){p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c])}}return p}('0(\'1\');',2,2,'alert|VYGY6'.split('|'),0,{}))

running it in any browser or online you get

the code is "VYGY6"

Hacky Easter 2017 Teaser , Riddle 3 Solution

RIDDLE 3

One for free here: 404 - not found! 

nothing seems in this code, checking the source code of the page (i use chrome inspect), i found under the text above the below script

document.write(String.fromCharCode(88, 73, 90, 76, 83));

running it in any browser or online you get

the code is "XIZLS"

Hacky Easter 2017 Teaser , Riddle 2 Solution

RIDDLE 2

UGllY2Ugb2YgY2FrZSEgWlhHSUQ=

checking the code above, it seems encoded or encrypted

so starting to decode it online

https://www.base64decode.org/

Piece of cake! ZXGID

so the code is "ZXGID"

Hacky Easter 2017 Teaser , Riddle 1 Solution

RIDDLE 2

MBD2A !ysaep ,ysaE

checking the code, it seems string is reversed

do it should be written

Easy, peasy! A2DBM

so the code is "A2DBM"