Hacky Easter 2017 Teaser , Riddle 16 Solution

RIDDLE 16

<~<+oue+DGm>FD,5.CghC,+E)./+Ws0B9h&:~>

this seems to be an encoded message, searching show it is ASCII85  encoded

using ASCII85 decoder online (https://www.tools4noobs.com/online_tools/ascii85_decode/)

the translated text is : This is the last one! DFMFZ

the code is "DFMFZ"

Hacky Easter 2017 Teaser , Riddle 15 Solution

RIDDLE 15

FRIDAY THE THIRTEENTH, 4:00 PM
/([FOR]*)([ID]{2})([^N]*)(.)(.*)/g
$2E$44

the second line is a regular expression, i tested the first line with it and it is ok

$2 and $44 capture parts of the check (good explanition is here http://stackoverflow.com/questions/5982824/what-does-1-2-etc-mean-in-regular-expressions)

i wrote the below javascript code to provide the $2 and $44

num="FRIDAY THE THIRTEENTH, 4:00 PM";
    re = /([FOR]*)([ID]{2})([^N]*)(.)(.*)/g;
    re.test(num);
    alert(num.replace(re, "$2,$44"));

this will alert ID,N4 adding to it the E

the code is "IDEN4"

Hacky Easter 2017 Teaser , Riddle 14 Solution

RIDDLE 14

89504E470D0A1A0A0000000D494844520000001D0000000708020000007BBCD1A5000000017352474200AECE1CE90000000467414D410000B18F0BFC6105000000097048597300000EC300000EC301C76FA8640000001874455874536F9180C0665A0582C8C7E22DF20C5480A130629060CF29792C16CB06293C82283C2F0C562540693C94F297F2983FB9D667477617265007061696E742E6E657420342E302E36FC8C63DF000001AA4944415428534D513DC8416118BD7E4A1EBF9BEDB77A673CE7DEE799FF3BE0CFB81C160904824C4098542C1E17098CDE672B90C399D4E9D4EA740208846A39954AD84EA9542E974B9A108BC5FF7301AD564B2F91CFE729174033BC1BF17EBFCFF87CBEF97C4E7ABBDDEAF57A90DBCD2693C9300CF3F5079A29168B56ABD5E572B5DBEDDF5C954A85B9D3E944D2EBF5D66AB5DBEDF67EBF5BADD6EBF51A8D4676BB1D9F7ABD9EDFEF877FBFDFE3F1782E97BB5EAFF0B1473A9D063F1C0E1A8D86CB1D8FC7D8CBE3F1341A0A194DBED7E3C1E8893CBE5E804743A1DEE57964DA552F57A1D64B7DB994C2632095CAE4C260B8542C160502A95AEDDC8C964A2502840FE83CF050987C3642693C96AB54A1C558810B8DC4824321C0E178B85CD66836C369BD80244A7D37EBC160100804E05F2E97E3F1882054E6F7DDEFF770CEE73378369BA5DCE7F3899B04E1C174BBDD582CF6FD01162F00000049454E44AE42608296C66341A3FA519FE5AD56A35A44824C2D99F71B652A9F0B9ABD5CA62B1604028142612891FA2F7838B729D41E800

this seems to be binary data, looking about the start and end, it seems it is a PNG picture

i wrote the below php script that take the data and save it as PNG file, open the file i found the code

$hexpic="89504E470D0A1A0A0000000D494844520000001D0000000708020000007BBCD1A500000017352474200AECE1CE90"
."000000467414D410000B18F0BFC6105000000097048597300000EC300000EC301C76FA8640000001874455874536F"
."667477617265007061696E742E6E657420342E302E36FC8C63DF000001AA4944415428534D513DC8416118BD7E4A1"
."9180C0665A0582C8C7E22DF20C5480A130629060CF29792C16CB06293C82283C2F0C562540693C94F297F2983FB9D"
."1A8D4676BB1D9F7ABD9EDFEF877FBFDFE3F1782E97BB5EAFF0B1473A9D063F1C0E1A8D86CB1D8FC7D8CBE3F1341A0"
."EBF9BEDB77A673CE7DEE799FF3BE0CFB81C160904824C4098542C1E17098CDE672B90C399D4E9D4EA740208846A39"
."BCD2693C9300CF3F5079A29168B56ABD5E572B5DBEDDF5C954A85B9D3E944D2EBF5D66AB5DBEDF67EBF5BADD6EBF5"
."DC8C964A2502840FE83CF050987C3642693C96AB54A1C558810B8DC4824321C0E178B85CD66836C369BD80244A7D3"
."A194DBED7E3C1E8893CBE5E804743A1DEE57964DA552F57A1D64B7DB994C2632095CAE4C260B8542C160502A95AED"
."954AD84EA9542E974B9A108BC5FF7301AD564B2F91CFE729174033BC1BF17EBFCFF87CBEF97C4E7ABBDDEAF57A90D"
."7EBC160100804E05F2E97E3F1882054E6F7DDEFF770CEE73378369BA5DCE7F3899B04E1C174BBDD582CF6FD01162F"
."96C66341A3FA519FE5AD56A35A44824C2D99F71B652A9F0B9ABD5CA62B1604028142612891FA2F7838B729D41E800"
."00000049454E44AE426082";

$data = pack("H" . strlen($hexpic), $hexpic);

file_put_contents("sample.png", $data);

the code is "AGBTC"

Hacky Easter 2017 Teaser , Riddle 13 Solution

RIDDLE 13

URER LBH TB: MJX4E

this also seems not easy, some sort of encryption, searching google a bit, i came across (https://www.geocaching.com/geocache/GC4MAT5_calliope?guid=83acce99-4599-46bb-86b7-6ef37d578708) 

this seems to be a substitution encryption, the key is

A B C D  E F G H I  J  K  L M

-------------------------------------N O P Q R S T U V W X Y Z


so doing the substitution for all letters (example A will be N and N will be A)

the translated text is : HERE YOU GO: ZWK4R

the code is "ZWK4R"

Hacky Easter 2017 Teaser , Riddle 12 Solution

RIDDLE 12

697c611778601371647d12177e7d060572
3133333731333337313333373133333731

the 2 lines are 34 chars, and seems to be hexadecimal, i tried many ways, and find out it is an XoR

i user (http://xor.pw/) and i get

584f522049532046554e21204f4e353243

using hexadecimal to Ascii converter http://www.rapidtables.com/convert/number/hex-to-ascii.htm()  i solved it

the translated text is : XOR IS FUN! ON52C

the code is "ON52C"

Hacky Easter 2017 Teaser , Riddle 11 Solution

RIDDLE 11

👻👽👻👻👻👻👽👽👻👽👻👻👽👽👽👽👻👽👻👻👽👽👽👻👻👽👻👻👻👽👽👽👻👽👻👽👻👻👽👻👻👽👻👻👻👻👻👽👻👽👻👽👻👽👻👻👻👽👻👽👻👻👽👽👻👻👽👻👻👻👻👽👻👻👽👻👻👻👻👻👻👽👻👻👽👽👽👻👻👻👽👽👻👽👻👽👻👽👻👽👽👻👻👻👻👽👻👻👻👽👽👽👻👽👻👻👽👻👽👽

as we only have 2 options (Black and white), it is a binary system

we have either black is 1 and white is 0 or the opposite

so either

010000110100111101001110010001110101001001000001010101000101001100100001001000000100111000110101010110000100011101001011
or

101111001011000010110001101110001010110110111110101010111010110011011110110111111011000111001010101001111011100010110100

check any binary to Ascii with both , we get the code
CONGRATS! N5XGK

the code is "N5XGK"

Hacky Easter 2017 Teaser , Riddle 10 Solution

RIDDLE 10

No comment.

as usual if nothing in the page, check the source code

the code is "A43JN"

Hacky Easter 2017 Teaser , Riddle 9 Solution

RIDDLE 9

Just a bit:
/2mi4AMj

this is very confusing, and take a lot of time and luck

searching google for bit and /2mi4AMj i came across this website

the code is "5DFME"

Hacky Easter 2017 Teaser , Riddle 8 Solution

RIDDLE 8

84 97 107 101 32 116 104 105 115 58 32 71 89 53 84 70

these seems to be ASCII codes, so i checked them online ( i use https://www.branah.com/ascii-converter)


the translated text is : T a k e   t h i s :   G Y 5 T F

the code is "GY5TF"

Hacky Easter 2017 Teaser , Riddle 7 Solution

RIDDLE 7

Hwldp wx, Euxwh! QYAVL

this seems to be an encryption some how, but it is not clear

doing a quick search for Euxwh on google, i found it as an example of Ceaser Cipher

so using Ceaser Cipher (explanation is here https://mysterytriplets.wordpress.com/2014/11/13/hw-wx-euxwh-learning-the-cesarean-cipher-3-letters-back/)

the code is "NVXSI"

Hacky Easter 2017 Teaser , Riddle 6 Solution

RIDDLE 6

--- -. . / -- --- .-. . / .... . .-. . ---... / .--- .- --- -- -.--

this looks like Morse code, using any online decode (i use http://morsecode.scphillips.com/translator.html )

the translated text is : ONE MORE HERE: JAOMY

the code is "KAOMY"

Hacky Easter 2017 Teaser , Riddle 5 Solution

RIDDLE 5

3a3ea00cfc35332cedf6e5e9a32e94da
9d5ed678fe57bcca610140957afab571
f09564c9ca56850d4cd6b3319e541aee
5dbc98dcc983a70728bd082d1a47546e
7fc56270e7a70fa81a5935b72eacbe29

as the code is 5 characters, then each line will be a letter 

trying with MD5 decode (i use http://md5decrypt.net/en/)

the code is "EBQSA"

Hacky Easter 2017 Teaser , Riddle 4 Solution

RIDDLE 4

eval(function(p,a,c,k,e,d){e=function(c){return c};if(!''.replace(/^/,String)){while(c--){d[c]=k[c]||c}k=[function(e){return d[e]}];e=function(){return'\\w+'};c=1};while(c--){if(k[c]){p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c])}}return p}('0(\'1\');',2,2,'alert|VYGY6'.split('|'),0,{}))

running it in any browser or online you get

the code is "VYGY6"

Hacky Easter 2017 Teaser , Riddle 3 Solution

RIDDLE 3

One for free here: 404 - not found! 

nothing seems in this code, checking the source code of the page (i use chrome inspect), i found under the text above the below script

document.write(String.fromCharCode(88, 73, 90, 76, 83));

running it in any browser or online you get

the code is "XIZLS"

Hacky Easter 2017 Teaser , Riddle 2 Solution

RIDDLE 2

UGllY2Ugb2YgY2FrZSEgWlhHSUQ=

checking the code above, it seems encoded or encrypted

so starting to decode it online

https://www.base64decode.org/

Piece of cake! ZXGID

so the code is "ZXGID"

Hacky Easter 2017 Teaser , Riddle 1 Solution

RIDDLE 2

MBD2A !ysaep ,ysaE

checking the code, it seems string is reversed

do it should be written

Easy, peasy! A2DBM

so the code is "A2DBM"